Reuben Township, Harlan County, Nebraska

Reuben Township
Township

Location in Harlan County
Coordinates: 40°13′11″N 099°27′24″W / 40.21972°N 99.45667°W / 40.21972; -99.45667Coordinates: 40°13′11″N 099°27′24″W / 40.21972°N 99.45667°W / 40.21972; -99.45667
Country United States
State Nebraska
County Harlan
Area
  Total 35.54 sq mi (92.04 km2)
  Land 35.52 sq mi (91.99 km2)
  Water 0.02 sq mi (0.05 km2)  0.05%
Elevation 2,192 ft (668 m)
Population (2000)
  Total 61
  Density 1.7/sq mi (0.7/km2)
GNIS feature ID 0838209

Reuben Township is one of sixteen townships in Harlan County, Nebraska, United States. The population was 61 at the 2000 census. A 2006 estimate placed the township's population at 56.[1]

See also

References

  1. "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Retrieved 2008-02-26.


This article is issued from Wikipedia - version of the 11/16/2013. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.