Alma Township, Harlan County, Nebraska
Alma Township | |
---|---|
Township | |
Location in Harlan County | |
Coordinates: 40°07′32″N 099°20′44″W / 40.12556°N 99.34556°WCoordinates: 40°07′32″N 099°20′44″W / 40.12556°N 99.34556°W | |
Country | United States |
State | Nebraska |
County | Harlan |
Area | |
• Total | 35.16 sq mi (91.06 km2) |
• Land | 34.17 sq mi (88.51 km2) |
• Water | 0.98 sq mi (2.55 km2) 2.8% |
Elevation | 2,090 ft (637 m) |
Population (2000) | |
• Total | 213 |
• Density | 6.2/sq mi (2.4/km2) |
GNIS feature ID | 0837850 |
Alma Township is one of sixteen townships in Harlan County, Nebraska, United States. The population was 213 at the 2000 census. A 2006 estimate placed the township's population at 195.[1]
See also
References
- ↑ "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Retrieved 2008-02-26.
External links
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