United States presidential election in Connecticut, 1988

United States presidential election in Connecticut, 1988

November 8, 1988

Nominee George H.W. Bush Michael Dukakis Party Republican Democratic Home state Texas Massachusetts Running mate Dan Quayle Lloyd Bentsen Electoral vote 8 0 Popular vote 750,241 676,584 Percentage 52.0% 46.9%

County Results   Dukakis—50-60%   Bush—50-60%

President before election Ronald Reagan Republican Elected President George H. W. Bush Republican

Elections in Connecticut
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The 1988 United States presidential election in Connecticut took place on November 8, 1988 as part of the 1988 United States presidential election, which was held throughout all 50 states and D.C. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts Governor Michael Dukakis, by a margin of 5.10%. Bush took 51.98% of the vote to Dukakis's 46.87%.

Although Dukakis won only Hartford County, he took 47-49% of the vote in five other counties, making it a close race statewide. He came much closer to winning the state than Walter Mondale, who had lost the state by over 20 points four years earlier. Dukakis's gains reflected liberal New England's drift as a whole toward the Democratic Party, as the Republican Party became increasingly conservative and oriented toward the South. This would be the last time that a Republican presidential candidate would win Connecticut's electoral votes, as the state has gone Democratic in every election since.

Results

Results by county

References

See also

State Results of the 1988 U.S. presidential election
Candidates	Michael Dukakis George H. W. Bush Ron Paul Lenora Fulani Full list
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Other 1988 elections	House Senate Gubernatorial