1986 FIFA World Cup qualification (CONMEBOL)
| Qualification for championships (CONMEBOL) |
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Listed below are the dates and results for the 1986 FIFA World Cup qualification rounds for the South American zone (CONMEBOL). For an overview of the qualification rounds, see the article 1986 FIFA World Cup qualification.
A total of 10 CONMEBOL teams entered the competition. The South American zone was allocated 4 places (out of 24) in the final tournament.
South America's qualifying berths were taken by Argentina, Uruguay, Brazil and Paraguay.
Tournament Structure
The 10 teams were divided into 3 groups. The teams played against each other on a home-and-away basis. The number of teams and spots for each group were as follows:
- Group 1 had 4 teams. The group winner would qualify. The runner-up and 3rd-placed team would advance to the CONMEBOL Play-offs.
- Groups 2 and 3 had 3 teams each. The group winners would qualify. The runners-up would advance to the CONMEBOL Play-offs.
In the Play-offs, the 4 teams played a in knockout tournament, with matches on a home-and-away basis. The tournament winner would qualify.
| Key to colours in group tables |
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Team qualifies for the World Cup |
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Team advances to the play-offs |
Group 1
Group 2
Group 3
Play-offs
First round
First Leg
Second Leg
Paraguay won 4–2 on aggregate and advanced to the Final Round.
Chile won 5–2 on aggregate and advanced to the Final Round.
Final round
First Leg
Second Leg
Paraguay won 5–2 on aggregate and qualified for the World Cup.
See also
External links
Colombia
Peru